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Calculating speed from height and time?
One Response to Calculating speed from height and time?
first u should know this formula:X2=1/2at^2+V1t+X1
here a is “-g” because armadillo is going up but g is downward.also we assume that X1 is earth surface,so it’s 0
then the formula changes to:X2= -1/2gt^2+V1t
now we got all the parameters except V1:
X2=.544 ,t=.200 ,g=9.8
.544=1/2×9.8x(.2^2)+.2xV1…so: .544=.196+.2xV1,then V1=.74/.2=3.7m/s
for finding V2 u just need to know that V2= -gt+V1
again we put minus for g because g is downward but the motion is upward.so:…V2= -9.8x.2+3.7…….so:V2=1.74m/s
and for finding How much higher does it go,first u should find the total amount of it’s height,then subtract .544 from it
do u know this formula?(V2)^2-(V1)^2= -2gX
V2 should be 0 here.because in the peak of it’s motion,it doesn’t have any speed.and again for the same reason we put a minus for g.
then wa got:0-(3.7)^2= -2×9.8xX,so:X=13.69/19.6=.698
so the last thing:X2-X1=.698-.544=.154m
hope i helped.:)
persian
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